4.8=2x^2

Solution for 4.8=2x^2 equation:

4.8=2x^2

We move all terms to the left:

4.8-(2x^2)=0

a = -2; b = 0; c = +4.8;
Δ = b2-4ac
Δ = 02-4·(-2)·4.8
Δ = 38.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{38.4}}{2*-2}=\frac{0-\sqrt{38.4}}{-4}
=-\frac{\sqrt{}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{38.4}}{2*-2}=\frac{0+\sqrt{38.4}}{-4}
=\frac{\sqrt{}}{-4}
$